I would like to match words starting with "ho" in a text. Matching words length should be maximum 5 and it should exclude hou in hour.
I currently struggle in adding length limits and excluding hou in hour.
My code is here:
demotext="what I have to do is to love you forever. however, we only have one hour left to be together. whatttttttttt. hot. hottest."
m = re.findall(r'\bwh\w+|\bho\w+',demotext)
print(m)
Can anyone tell me how to do it?
You can use
\b(?:wh|ho(?!ur\b))[a-zA-Z]{1,3}\b
If the hours should also be excluded, add s? after r,
\b(?:wh|ho(?!urs?\b))[a-zA-Z]{1,3}\b
See the regex demo.
Regex details
\b - a word boundary(?:wh|ho(?!urs?\b)) - Group 1: either wh, or ho not followed with ur and an optional s and a word boundary[a-zA-Z]{1,3} - one, two or three letters\b - a word boundary.Python demo
import re
text = r"what I have to do is to love you forever. however, we only have one hour left to be together. whatttttttttt. hot. hottest."
print(re.findall(r'\b(?:wh|ho(?!ur\b))[a-zA-Z]{1,3}\b', text))
# => ['what', 'hot']