Python, make a chore list without the same output twice

user_14429401 0
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import random
names = ['Gio', 'Dano', 'Gian']
chores = [ 'Dookies', 'Restroom', 'Floor']
name = random.choice (names)
chore = random.choice (chores)
phrase = name + '' + chore +''
print (phrase)

I want this to be a random selection to end up like Gio Dookies, Dano Floor, Gian Restroom randomly randomly randomly etc. Thank you

python-3.x python
2 Answers

Use random.shuffle to shuffle the list of chores (no need to shuffle the names). Then, for each index in the names list, print the name at this index together with the chore at the index.

When your requirements are more complex (size of names and chores doesn't match, pairings of name/chore shouldn't repeat etc.) you need a more complex algorithm, of course.

user_63879480

You can first shuffle the list of chores to ensure the order is random, and then pop elements from this list one by one (therefore returning them, while also dropping them from the list reference). For example:

import random
names = ['Gio', 'Dano', 'Gian']
chores = [ 'Dookies', 'Restroom', 'Floor']
random.shuffle(chores) # this shuffles inplace, so no need to reassign
for name in names:
    chore = chores.pop() # returns the last element of the chores
    phrase = name + ' ' + chore +' '
    print (phrase)

This will effectively assign every one of your names (people) to a chore in the list of chores. It's useful because you can also have duplicate chores (for example you need 2 people to do the "Floor"), and that can be reflected in your list from which you pop().

user_103547890
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