for loops in python
Gilad Green already answered your question with a way to fix your code and a quick explanation on for loops.
Here are five loops that do more or less the same thing; I invite you to try them out.
particulars = (("S12345", "John"), ("S23456", "Max"), ("S34567", "Mary"))
for t in particulars:
print("{} {}".format(t[0], t[1]))
for i in range(len(particulars)):
print("{}: {} {}".format(i, particulars[i][0], particulars[i][1]))
for i, t in enumerate(particulars):
print("{}: {} {}".format(i, t[0], t[1]))
for reg_value, student_name in particulars:
print("{} {}".format(reg_value, student_name))
for i, (reg_value, student_name) in enumerate(particulars):
print("{}: {} {}".format(i, reg_value, student_name))
Using dictionaries instead of lists
Most importantly, I would like to add that using an unsorted list to store your student records is not the most efficient way.
If you sort the list and maintain it in sorted order, then you can use binary search to search for reg_num much faster than browsing the list one item at a time. Think of this: when you need to look up a word in a dictionary, do you read all words one by one, starting by "aah", "aback", "abaft", "abandon", etc.? No; first, you open the dictionary somewhere in the middle; you compare the words on that page with your word; then you open it again to another page; compare again; every time you do that, the number of candidate pages diminishes greatly, and so you can find your word among 300,000 other words in a very small time.
Instead of using a sorted list with binary search, you could use another data structure, for instance a binary search tree or a hash table.
But, wait! Python already does that very easily!
There is a data structure in python called a dictionary. See the documentation on dictionaries. This structure is perfectly adapted to most situations where you have keys associated to values. Here the key is the reg_number, and the value is the student name.
You can define a dictionary directly:
particulars = {'S12345': 'John', 'S23456': 'Max', 'S34567': 'Mary'}
Or you can convert your list of tuples to a dictionary:
particulars = (("S12345", "John"), ("S23456", "Max"), ("S34567", "Mary"))
particulars_as_dict = dict(particulars)
Then you can check if an reg_number is in the dictionary, with they keyword in; you can return the student name using square brackets or with the method get:
>>> particulars = {'S12345': 'John', 'S23456': 'Max', 'S34567': 'Mary'}
>>> 'S23456' in particulars
True
>>> 'S98765' in particulars
False
>>>
>>> particulars['S23456']
'Max'
>>> particulars.get('S23456')
'Max'
>>> particulars.get('S23456', 'not found')
'Max'
>>>
>>> particulars['S98765']
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
KeyError: 'S98765'
>>> particulars.get('S98765')
None
>>> particulars.get('S98765', 'not found')
'not found'