I have built a custom Keras model which consists of various layers. Since I wanted to add L2 regularization to such layers, I've passed an instance of keras.regularizers.l2 as the argument for the kernel_regularizer parameter of those layers (as an example, see the constructor of keras.layers.Conv2D). Now, if I were to train this model using, say, Keras's implementation of the binary cross-entropy loss (keras.losses.BinaryCrossEntropy), I would be sure that the L2 regularization that I've specified would be taken into consideration when computing the loss.
In my case, however, I have a custom loss function that requires several other parameters aside from y_true and y_pred, meaning that there's no way I can pass this function as the argument for the loss parameter of model.compile(...) (in fact, I don't even call model.compile(...)). As a result, I also had to write a custom training loop. In other words, instead of simply running model.fit(...), I had to:
- Perform forward propagation by calling
model(x) - Compute the loss
- Compute the gradients of the loss with respect to the model's weights (that is,
model.trainable_variables) withtf.GradientTape - Apply the gradients
- Repeat
My question is: in which phase is regularization accounted for?
- During forward propagation?
- During the computation/application of the gradients?
Keep in mind that my custom loss function does NOT account for regularization, so if it's not accounted for in any of the two phases I've mentioned above, then I'm actually training a model with no regularization whatsoever (even though I've provided a value for the kernel_regularizer argument in each layer that my network is made of). In that case, would I be forced to compute the regularization term by hand and add it to the loss?