Need help printing list

user_14270356 0
Viewed 98

I'm working on a todo list in Python and I am currently stuck on printing the todo list.

I have my add code and view code as such:

if sel == '1': #add task        
     name = input("enter task name: ")
     prio = input("enter priority level (High | Medium | Low): ")
     add(todo, name, prio)
     view(task)
elif sel == '3': #print todo list
     view2(task)
     exit

and these are the functions im using:

def add(todo, x, y):
    todo[x] = y

def view(x):
    x.append(dict(todo))

def view2(x):
    print(x)

I'm able to add items to a dictionary print the dictionary the first time i select the option to print list. The second time i print it gives the below output

[{'test 1': 'low'}, {'test 1': 'low', 'test 2 ': 'low'}]

my ultimate goal is to get an output as shown below, but i can't get passed this first wall. Any advice? also, would i need to print a nested dictionary to get a numbered list?

1 - test 1 - low
2 - test 2 - low

Thanks in advance !

zsh python
2 Answers

Assuming view2(x) is the function for printing and x is the dictionary which you have mentioned in the question.

You can do something like this

def view2(x):
    for key, val in x.items():
        print("{0} - {1}".format(key, val))
user_91077860

This code will work for any number of todos in the list.

todo_list = [{'test 1': 'low'}, {'test 2': 'low'}]
def show(todo_list):
    for index, todo in enumerate(todo_list, start=1):
        for key in todo.keys(): 
            print(index, key, todo[key])

show(todo_list)
user_136464300
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