TypeError: request() missing 1 required positional argument: 'url' in urllib3

user_13863917 0
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I'm getting deep into Python and was going through urllib3's docs. Tried running the code but seems like it's not working the way it's expected to. My code is

import urllib3

t = urllib3.PoolManager
test = t.request('GET', 'https://shadowhosting.net/')
print(test.data)

And the error I get is

TypeError: request() missing 1 required positional argument: 'url'

I tried swapping place but still not working. I'm following the very beginning of the documentation(User Guide) For reference - https://urllib3.readthedocs.io/en/latest/user-guide.html

urllib3 python
3 Answers

It's a typo forgot the parenthesis to create an object:

t = urllib3.PoolManager()

Add them and it shall work like magic:

import urllib3

t = urllib3.PoolManager()
test = t.request('GET', 'https://shadowhosting.net/')
print(test.data)
user_141488640

if you want to make GET request to URL then you can use requests module

import requests

response = requests.get('https://shadowhosting.net/')
print(response.text)
user_127551870

The docs at https://urllib3.readthedocs.io/en/latest/user-guide.html says :

    import urllib3

    http = urllib3.PoolManager()    //You were missing this paranthesis
    r = http.request('GET', 'http://httpbin.org/robots.txt')

OR in case of POST request

r = http.request('POST','http://httpbin.org/post', fields={'hello': 'world'})
user_64706130
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