How to terminate loop.run_in_executor with ProcessPoolExecutor gracefully? Shortly after starting the program, SIGINT (ctrl + c) is sent.
def blocking_task():
sleep(3)
async def main():
exe = concurrent.futures.ProcessPoolExecutor(max_workers=4)
loop = asyncio.get_event_loop()
tasks = [loop.run_in_executor(exe, blocking_task) for i in range(3)]
await asyncio.gather(*tasks)
if __name__ == "__main__":
try:
asyncio.run(main())
except KeyboardInterrupt:
print('ctrl + c')
With max_workers equal or lesser than the the number of tasks everything works. But if max_workers is greater, the output of the above code is as follows:
Process ForkProcess-4:
Traceback (most recent call last):
File "/usr/lib/python3.8/multiprocessing/process.py", line 315, in _bootstrap
self.run()
File "/usr/lib/python3.8/multiprocessing/process.py", line 108, in run
self._target(*self._args, **self._kwargs)
File "/usr/lib/python3.8/concurrent/futures/process.py", line 233, in _process_worker
call_item = call_queue.get(block=True)
File "/usr/lib/python3.8/multiprocessing/queues.py", line 97, in get
res = self._recv_bytes()
File "/usr/lib/python3.8/multiprocessing/connection.py", line 216, in recv_bytes
buf = self._recv_bytes(maxlength)
File "/usr/lib/python3.8/multiprocessing/connection.py", line 414, in _recv_bytes
buf = self._recv(4)
File "/usr/lib/python3.8/multiprocessing/connection.py", line 379, in _recv
chunk = read(handle, remaining)
KeyboardInterrupt
ctrl + c
I would like to catch the exception (KeyboardInterrupt) only once and ignore or mute the other exception(s) in the process pool, but how?
Update extra credit:
- Can you explain (the reason for) the multi exception?
- Does adding a signal handler work on Windows?
- If not, is there a solution that works without a signal handler?