Carry on index after cutting a list

user_11991051 0
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I have a list:

l1 = [2, 3, 5, 7, 11, 13]

With the indexes and values:

ind  val
 0    2
 1    3
 2    5
 3    7
 4    11
 5    13

Now I slice the array with:

l2 = l1[3:]

And get:

ind  val
 0    7
 1    11
 2    13

But I want the indexes to remain the same as they were before the cutting:

ind  val
 3    7
 4    11
 5    13
slice list python
1 Answers

With Pandas and series:

import pandas as pd

list=[2, 3, 5, 7, 11, 13]

x = pd.Series(list) 

# Display sub serie
x.iloc[3:]

# Display sub serie values as a list
x.iloc[3:].tolist()

# Display sub serie index as a list
x.iloc[3:].index.tolist()
user_119050800
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