The priority of require () 's parameter to determine the file-extension in nodejs

Question

I am learning node.js

for example, I try

var server = require("./myserver.js");

and

var server = require("./myserver");

Both of these two casework.

what if I have another file with the same name? e.g myserver.json, myserver.node , will it always search .js at first?

From one of the answerers in my previous question, he mentions only load the .json file if you explicitly add the .json extension to the require-call. So if you leave the extension, it always loads the .js file.

will this rule also suit to .node file?

user_10848737 · Answer

If the exact filename is not found, then Node.js will attempt to load the required filename with the added extensions: .js, .json, and finally .node. You can check node_js docs for detailed explanation. https://nodejs.org/api/modules.html#modules_file_modules

user_14058058 · Answer

Yes, If you will not provide the extension of the file, Then, it will first look at the JS file, since JS is by default

The priority of require () 's parameter to determine the file-extension in nodejs

2 Answers