Group by column and multiple Rows into One Row multiple columns

user_14142514 0
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Please help me this:

I want to group by column TestType, but Result should be splitted into colunms if they have same TestType

CREATE TABLE Result(WorkOrder varchar(10), TestType varchar(20), Result decimal(10,2));
INSERT INTO Result (WorkOrder, TestType, Result) VALUES 
('HP19002316','VitaminA', 10.3),
('HP19002316','VitaminA', 11.3),
('HP19002316','VitaminA', 12.3),
('HP19002316','VitaminB', 13.4),
('HP19002316','VitaminB', 14.4),
('HP19002316','VitaminC', 15.5),
('HP19002316','VitaminD', 17.0)

I want SQL to return data in this format

WorkOrder       TestType        Result1   Result2  Result3 
==========================================================
HP19002316      VitaminA        10.3        11.3    12.3    
HP19002316      VitaminB        13.4        14.4    NULL
HP19002316      VitaminC        15.5        NULL    NULL
HP19002316      VitaminD        17.0        NULL    NULL

Result# column should be dynamic because each TestType has many Results

sql-server sql
2 Answers

As I mention in the comments, what you need here is a PIVOT or Cross tab; I prefer the latter so what I am going to use.

The non-dynamic solution to this would be as follows:

WITH RNs AS(
    SELECT WorkOrder,
           TestType,
           Result,
           ROW_NUMBER() OVER (PARTITION BY WorkOrder, TestType ORDER BY (SELECT NULL)) AS RN --ORDER BY should be your ID/always ascending column
    FROM dbo.Result)
SELECT WorkOrder,
       TestType,
       MAX(CASE RN WHEN 1 THEN Result END) AS Result1,
       MAX(CASE RN WHEN 2 THEN Result END) AS Result2,
       MAX(CASE RN WHEN 3 THEN Result END) AS Result3
FROM RNs R
GROUP BY WorkOrder,
         TestType;

The problem, however, is that this "locks" you into 3 results, but you suggest there is an indeterminate number of results. Therefore you need a dynamic solution.

The below will work up to 100 results. if you do need more columns than than, then add more CROSS JOINs to N in the CTE Tally. This results is something like this (which is quite messy).

DECLARE @SQL nvarchar(MAX),
        @CRLF nchar(2) = NCHAR(13) + NCHAR(10),
        @MaxTally int;

SELECT @MaxTally = MAX(C)
FROM (SELECT COUNT(*) AS C
      FROM dbo.Result
      GROUP BY WorkOrder,
               TestType) R;

WITH N AS(
    SELECT N
    FROM (VALUES(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL))N(N)),
Tally AS(
    SELECT TOP (@MaxTally) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS I
    FROM N N1, N N2) --100 rows, add more Ns for more rows
SELECT @SQL = N'WITH RNs AS(' + @CRLF +
              N'    SELECT WorkOrder,' + @CRLF +
              N'           TestType,' + @CRLF +
              N'           Result,' + @CRLF +
              N'           ROW_NUMBER() OVER (PARTITION BY WorkOrder, TestType ORDER BY (SELECT NULL)) AS RN --ORDER BY should be your ID/always ascending column' + @CRLF +
              N'    FROM dbo.Result)' + @CRLF +
              N'SELECT WorkOrder,' + @CRLF +
              N'       TestType,' + @CRLF +
              --Using FOR XML PATH due to not knowing SQL Server version
              STUFF((SELECT N',' + @CRLF +
                            CONCAT(N'       MAX(CASE RN WHEN ',T.I,N' THEN Result END) AS Result',T.I)
                     FROM Tally T
                     ORDER BY T.I ASC
                     FOR XML PATH(N''),TYPE).value('(./text())[1]','nvarchar(MAX)'),1,3,N'') + @CRLF +
              N'FROM RNs R' + @CRLF +
              N'GROUP BY WorkOrder,' + @CRLF +
              N'         TestType;';

PRINT @SQL; --Your best friend.

EXEC sys.sp_executesql @SQL;
user_20299830

You may try this and extend the logic.

select *,((select Result from (select TestType,Result, ROW_NUMBER() over ( PARTITION BY testtype ORDER BY  Testtype) Id from Result) a where a.Id='1' and a.TestType=b.TestType )) Result1,
((select Result from (select TestType,Result, ROW_NUMBER() over ( PARTITION BY testtype ORDER BY  Testtype) Id from Result) a where a.Id='2' and a.TestType=b.TestType )) Result2,
((select Result from (select TestType,Result, ROW_NUMBER() over ( PARTITION BY testtype ORDER BY  Testtype) Id from Result) a where a.Id='3' and a.TestType=b.TestType )) Result3
 from (
select Max(WorkOrder) WorkOrder,TestType from Result group by TestType ) b
user_65780550
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