I need to get an iterator based on offset.
i.e. having the iterator for begin :
auto it = set.begin()
I need to get to the iterator having offset ofst:
it + ofst
Is there a way to do that? of I need incremental increase it++ the iterator ofst times.
I need to get to the iterator having offset
ofst:it + ofst: is there a way to do that?
No, there is no operator+ overload defined for this for std::set::iterator (aka bidirectional iterators). However, you can use std::next, from <iterator> header as follows to achive the same.
#include <iterator> // std::next
auto nthIter = std::next(it, ofst);
This basically behind the scene increments ofst times too.
The std::set has bidirectional iterators, which has no luxuries like random access iterators, and hence need to increment like this.
That being said, you could overload the operator+(and maybe operator-) for the bidirectional iterators, which will not be recommended though.