Python Beautifulsoup, get href tag, in a tag

user_12703449 0
Viewed 5695

i had problem with getting href tag, so my case like this, this is the html file :

<div class="list-product with-sidebar">
 <a class="frame-item" href="./produk-a.html" target="_blank" title="Produk A">

 </a>
 <a class="frame-item" href="./produk-b.html" target="_blank" title="Produk B">

 </a>
</div>

so here my code

    def get_category_item_list(category):
        base_url = 'https://www.website.com/'
        res = session.get(base_url+category)
        res = BeautifulSoup(res.content, 'html.parser')
        all_title = res.findAll('a', attrs={'class':'frame-item'})
        data_titles = []
        for title in all_title:
            product_link = title.get('a')['href']
            data_titles.append(product_link)
        return data_titles

what i want to get is, href links.. like this

produk-a.html
produk-b.html

when i try to run it.. it wont let me get link on href, they give error code :

TypeError: 'NoneType' object is not subscriptable
web-scraping beautifulsoup html python
3 Answers

I believe that your problem lies in this line :

product_link = title.get('a')['href']

You already have a list of "a" elements, so you probably just need :

product_link = title['href']
user_33224000

You didn't share with us the website, so one problem might be that the website block User Agents that looks like a bot (requests's user agent). Debugging may help here, you can print the content of the page with resp.content/text.

I created an HTML file called index.html and then I read the file and scrape it's content. I changed a little bit the code and it seems to be work fine.

soup.find returns an <class 'bs4.element.Tag'>, so you can access it's attributes with attribute['a'].

from bs4 import BeautifulSoup

with open('index.html') as f:
    html_content = f.read()

soup = BeautifulSoup(html_content, 'html.parser')
data_titles = []
for a in soup.find('div', class_='list-product with-sidebar').find_all('a'):
    data_titles.append(a['href'].split('/')[1])
print(data_titles)
# ['produk-a.html', 'produk-b.html']

index.html

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="UTF-8" />
        <meta name="viewport" content="width=device-width, initial-scale=1.0" />
        <title>Document</title>
    </head>
    <body>
        <div class="list-product with-sidebar">
            <a
                class="frame-item"
                href="./produk-a.html"
                target="_blank"
                title="Produk A"
            >
            </a>
            <a
                class="frame-item"
                href="./produk-b.html"
                target="_blank"
                title="Produk B"
            >
            </a>
        </div>
    </body>
</html>
user_139981630

For your exact output,

  1. you are already iterating over anchor tags
  2. you would need to split by "/" and choose the last element
from bs4 import BeautifulSoup


html = """<div class="list-product with-sidebar">
 <a class="frame-item" href="./produk-a.html" target="_blank" title="Produk A">

 </a>
 <a class="frame-item" href="./produk-b.html" target="_blank" title="Produk B">

 </a>
</div>"""

res = BeautifulSoup(html, 'html.parser')

for a in res.findAll('a', attrs={'class':'frame-item'}):
    print(a["href"].split("/")[-1])

Output:

produk-a.html
produk-b.html
user_68496820
Related