I have data like this (file is called list-in.dat)
a ; b ; c ; i
d
e ; f ; a ; b
g ; h ; i
and I want a list like this (output file list-out.dat) with all items, in alphabetically order (case insensitive) and each unique item only once.
a
b
c
d
e
f
g
h
i
My attempt is:
awk -F " ; " ' BEGIN { OFS="\n" ; } {for(i=0; i<=NF; i++) print $i} ' file-in.dat | uniq | sort -uf > file-out.dat
But I end up with all antries except those lines which has only one item:
a
b
c
e
f
g
h
i
How can I get all (unique, sorted) items no matter how many items are in one line / if the field separator is missing?