Check if an array includes some special characters

user_10563344 0
Viewed 635

I am trying to check if a password string contains some special characters.
I am trying to implement that with the following code:

const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) => {
  specialChar.includes(letter);
});

However, hasSpecLet returns false.

array-formulas arrays javascript
5 Answers

You're missing the return statement in the function you're passing to some():

const hasSpecLet = passwordArr.some((letter) => {
  return specialChar.includes(letter);
});

Or just use a terser version (without the curly braces):

const hasSpecLet = passwordArr.some(letter => specialChar.includes(letter));

See MDN

user_16257370

whenever you are using { } inside an arrow function you have to use return keyword O.W. values are returned by default.

const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) => {
   return specialChar.includes(letter);
});
console.log(hasSpecLet);

user_110162750

You need to use return since the arrow function uses curly braces:

const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) => {
  return specialChar.includes(letter);
});
console.log(hasSpecLet);

Or do the following: 

const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) => 
  specialChar.includes(letter)
);
console.log(hasSpecLet);

user_74863130

This small change will make it work -

const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) => 
  specialChar.includes(letter)
);

console.log(hasSpecLet)

The above change will make sure that the value processed by - specialChar.includes(letter) gets returned and used in the parent function to give the final result.

In your case, none of the letters returned a true value and hence you would have got false in every case

user_136020760

Using some() and include()

const hasSpecLet  = passwordArr.some((letter) => specialChar.includes(letter))

Using intersection

const hasSpecLet = passwordArr.filter(value => specialChar.split('').includes(value)).length !== 0
user_26173440
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