Find an object with biggest semver version

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Let's say I have some documents in MongoDB with a version property(semver version), for example something like { ..., version: { major: 1, minor: 2, patch: 13 } }, or { ..., version: "1.2.13" }, i haven't decided yet which format i will be using.

I need to find the document with the highest version.
For example, if collection has two documents with {..., version: "0.10.0"} and {..., version: "1.0.0"} then i would like to get document with version = "1.0.0"

I'm using Spring Data MongoDB, so ideally i would like to find some solution by using Criteria API

spring-data spring-data-mongodb mongodb criteria spring
1 Answers

It turned out to be quite simple when i use first format of version:
{ ..., version: { major: 1, minor: 2, patch: 13 } }

Then i can just sort by all those three fields and take the one top document:

db.metadata.find({})
   .projection({})
   .sort({ "version.major": -1, "version.minor": -1, "version.patch": -1 })
   .limit(1)

This query is written by using Criteria API:

public Metadata getLatestMetadata() {
    Criteria criteria = Criteria
            .where("type").is(TEST_TYPE);

    Query query = Query.query(criteria).with(getVersionSort()).limit(1);
    return mongoOperations.findOne(query, Metadata.class);
}

private Sort getVersionSort() {
    return Sort.by(new Sort.Order(Sort.Direction.DESC, "version.major"),
            new Sort.Order(Sort.Direction.DESC, "version.minor"),
            new Sort.Order(Sort.Direction.DESC, "version.patch"));
}
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