I have a list that contains pair of keywords ('k1', 'k2'). Here's a sample:
print (word_pairs)
--->[('salaire', 'dépense'), ('gratuité', 'argent'), ('causesmwedemwelamwemort', 'cadres'), ('caractèresmwedumwedispositif', 'historique'), ('psychomotricienmwediplôme', 'infirmier'), ('impôtmwesurmwelesmweréunionsmwesportives', 'compensation'), ('affichage', 'affichagemweopinion'), ('délaimweprorogation', 'défaillance'), ('créancemwenotion', 'généralités')]
I have a text file r_isa.txt (205MB) that contain words that share an "isa" relationship. Here's a sample, where \t represents a literal tab character:
égalité de Parseval\tformule_0.9333\tégalité_1.0
filiation illégitime\tfiliation_1.0
Loi reconnaissant l'égalité\tloi_1.0
égalité entre les sexes\tégalité_1.0
liberté égalité fraternité\tliberté_1.0
This basically means, "égalité de Parseval" isa "formule" with a score of 0.9333 and isa "égalité" with a score of 1. And so go on..
I want to know based on the r_isa file, if the keyword k1 isa k2, and if k2 is-a k1. On the output file, I want to save on each line the pair of words that do have the is-a relationship.
Here's what I did:
#Reading data as list
keywords = [line for line in open('version_final_PMI_espace.txt', encoding='utf8')]
keywords = ast.literal_eval(keywords[0])
word_pairs = []
for k,v in keywords.items():
if v:
word_pairs.append((k,v[0][0]))
len(list(set(word_pairs)))
#####
with open("r_isa.txt",encoding="utf-8") as readfile, open('Hyperonymy_file_pair.txt', 'w') as writefile:
for line in readfile:
firstfield = line.split('\t')[0].lower()
for w in word_pairs:
if w[0]==firstfield:
if w[1] in line:
writefile.write("".join(w[0]) + "\t"+"".join(w[1]) +"\n" )
This returns random pairs to me, for exemple:
salaire\targent
dépense\tcadres
unstead of ( in case of an existing isa relationship)
salaire\tdépense
causesmwedemwelamwemort\tcadres
Where did I go wrong ?