Compare dicts but get result with source

user_8614825 0
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Hello I need to compare 2 dicts but in the result, I need to know from which dict the result came.

dict1 = {'name': 'Morgan', 'surename': 'Finch'}
dict2 = {'name': 'David', 'surename': 'Finch'}

so if I compare with input_data.items() ^ response_data.items() result will something like this:

{('name','Morgan'),('name', 'David)}

expected result should look something like {'dict1': ('name','Morgan'), dict2: ('name', 'David')} I don't care what data-structure just that I could know from what dict it came.

python-3.x python
2 Answers
dict1 = {'name': 'Morgan', 'surname': 'Finch'}
dict2 = {'name': 'David', 'surname': 'Finch'}

# symmetric difference (exclusive OR)
print(dict1.items() ^ dict2.items())
# {('name', 'Morgan'), ('name', 'David')}

# dictionary subtraction
print({'dict1': dict1.items() - dict2.items(), 'dict2': dict2.items() - dict1.items()})
# {'dict1': {('name', 'Morgan')} 'dict2': {('name', 'David')}}
user_140563970

If you want the answer in the form of dictionary

You can use these steps

dict1 = {'name': 'Morgan', 'surename': 'Finch'}
dict2 = {'name': 'David', 'surename': 'Finch'}

dict3 = {}

for k,v in dict1.items():
    if dict1[k] != dict2[k]:
        dict3['dict1'] = (k,dict1[k])
        dict3['dict2'] = (k,dict2[k])
        
print(dict3)

Output:

{'dict1': ('name', 'Morgan'), 'dict2': ('name', 'David')}

Edit:

If all values are different and want to store in a single key like {'dict1' : ('name', 'Morgan', 'surname', 'Finc'), ... }

dict1 = {'name': 'Morgan', 'surename': 'Finch'}
dict2 = {'name': 'David', 'surename': 'Finc'}

dict3 = {'dict1':(), 'dict2':()}

for k,v in dict1.items():
    if dict1[k] != dict2[k]:
        dict3['dict1'] += (k,dict1[k])
        dict3['dict2'] += (k,dict2[k])
        
print(dict3)

Output:

{'dict1': ('name', 'Morgan', 'surename', 'Finch'), 'dict2': ('name', 'David', 'surename', 'Finc')}
user_124785310
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