Include type information when dereferencing?

user_1684269 0
Viewed 163

When dereferencing an argument within a function call like this:

worker.onmessage = ({ data }) =>

Is there a way to include typing information?

For example in this case the dereferenced data object is a ParseResult. Can we include that somehow within the dereferencing syntax?

The end goal is to get autocomplete working within the function.

I could do something like:

const result:ParseResult = data

But I'm curious as to whether there is a shorter more sugared approach?

typescript destructuring function-parameter
2 Answers

Unfortunately one cannot put types directly on the individual identifiers in the destructuring pattern, one can only type the whole parameter:

worker.onmessage = ({ data }: { data: ParseResult }) =>
user_10485720

Is this what you want (not sure to understand your question)

interface ParseResult{
    data: string;
}

const testder = ({ data }: ParseResult) =>{
    console.log(data);
}


const para:ParseResult= {
    data:"test"
}

testder(para)
user_91683900
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