group by year and boolean column postgres

user_7475879 0
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I have the following table

id   |  created_on   | is_a   | is_b    | is_c
----------------------------------------------
1    |  01-02-1999   | True   |False    |False
2    |  23-05-1999   | False  |True     |False
3    |  25-08-2000   | False  |True     |False
4    |  30-07-2000   | False  |False    |True
5    |  05-09-2001   | False  |False    |True
6    |  05-09-2001   | False  |True     |False
7    |  05-09-2001   | True   |False    |False
8    |  05-09-2001   | True   |False    |False

In the table resulting the query, I would like to group by year of creation, and then be able to compare how many records were created in each year for is_a and is_b. I want to completely ignore from the count is_c.

count_a | count_b  | by_creation_year
-----------------------------------------------
1       |1         | 1999
0       |1         | 2000
2       |1         | 2001

I tried the following query:

select count(is_a = True) a, 
       count(is_b = True) b,
       date_trunc('year', created_on)
from cp_all
where is_c = False  -- this removes the records where is_c is True
group by date_trunc('year', created_on)
order by date_trunc('year', created_on) asc;

But I get a table where the count of a and b is exactly the same.

group-by date postgresql sql
3 Answers

Your count() argument evaluates to true or false which each gets counted as 1 regardless.

You want to use filter

select count(*) filter (where is_a) a, 
       count(*) filter (where is_b) b,
       date_trunc('year', created_on)
  from cp_all
 where is_c = False  -- this removes the records where is_c is True
 group by date_trunc('year', created_on)
 order by date_trunc('year', created_on) asc;

Doing it this way you will not need the where clause.

user_138083190

That's because count does not take boolean expressions it simply uses the expression and evaluates to check whether it is null or not null to add to the counter. So in this case you should use sum with case

select sum(case when is_a then 1 else 0 end) a, 
       sum(case when is_b then 1 else 0 end) b,
       date_trunc('year', created_on)
from cp_all
where is_c = False  -- this removes the records where is_c is True
group by date_trunc('year', created_on)
order by date_trunc('year', created_on) asc;
user_4605570

Although I like filter, this is simpler to type:

select sum(is_a::int) as a, 
       sum(is_b::int) as b,
       date_trunc('year', created_on)
from cp_all
where is_c = False  -- this removes the records where is_c is True
group by date_trunc('year', created_on)
order by date_trunc('year', created_on) asc;
user_11440350
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