I am wondering if it's possible to obtain the result of percentile_rank using the QuantileDiscretizer transformer in pyspark.
The purpose is that I am trying to avoid computing the percent_rank over the entire column, as it generates the following error:
WARN WindowExec: No Partition Defined for Window operation!
Moving all data to a single partition, this can cause serious performance degradation.
The method I am following is to first use QuantileDiscretizer then normalize to [0,1]:
from pyspark.sql.window import Window
from pyspark.ml.feature import QuantileDiscretizer
from scipy.stats import gamma
X1 = gamma.rvs(0.2, size=1000)
df = spark.createDataFrame(pd.DataFrame(X1, columns=["x"]))
df = df.withColumn("perc_rank", F.percent_rank().over(Window.orderBy("x")))
df = QuantileDiscretizer(numBuckets=df.count()+1,\
inputCol="x",\
outputCol="q_discretizer").fit(df).transform(df)
agg_values = df.agg(F.max(df["q_discretizer"]).alias("maxval"),\
F.min(df["q_discretizer"]).alias("minval")).collect()[0]
xmax, xmin = agg_values.__getitem__("maxval"), agg_values.__getitem__("minval")
normalize = F.udf(lambda x: (x-xmin)/(xmax-xmin))
df = df.withColumn("perc_discretizer", normalize("q_discretizer"))
df = df.withColumn("error", F.round(F.abs(F.col("perc_discretizer")- F.col("perc_rank")),6) )
print(df.select(F.max("error")).show())
df.show(5)
However, it seems that increasing the number of datapoints the error grows, so I am not sure this is the right way to do it.
Is it possible to use QuantileDiscretizer to obtain the percentile_rank?
Alternatively is there a way to compute percentile_rank over an entire column in an efficient way?