Difference between r2_score and score() in linear regression

user_13827086 0
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I found the results of score() in LinearRegression is different from r2_score(). I expected them to return the same results.The codes are as below:

r2_train = np.empty(shape=[10, 0])
r2_train_n = np.empty(shape=[10, 0])

for set_degree in range (0,10):
    pf = PolynomialFeatures(degree= set_degree)
    X_train_tf = pf.fit_transform(X_train.reshape(11,1))
    X_test_tf = pf.transform(X_test.reshape(4,1))
    lr = LinearRegression().fit(X_train_tf, y_train)

    r2_train = np.append(r2_train, r2_score(lr.predict(X_train_tf), y_train))
    r2_train_n = np.append(r2_train_n, lr.score(X_train_tf, y_train))
scikit-learn linear-regression machine-learning python
2 Answers

score() :- It is just comparing the error/residual in between the actual values and the predicted values.

r2_score() :- it is the value which specifies the amount of the residual across the whole dataset.

The r2 score is more robust and quite often used accuracy matrix.

It is calculated as

(r2_score = 1 - (RSS / TSS))

Where(RSS = Residual Sum of Sqaure & TSS = Total Sum of sqaure). While performing the regression by using the OLS method you should also consider the value of adjustedR2

user_107637500

In using r2_score, you made it:

r2_score(lr.predict(X_train_tf), y_train)

According to the documentation, the first argument should be the true values, i.e. it should be:

r2_score(y_train, lr.predict(X_train_tf))

This will give similar result with the score method in LinearRegression()

Same question here

user_95395380
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