Sorting strings of letters, numbers, and special characters

I have a list of strings that I would like to sort in a particular order.

The list is ["Bea", "hel", "Hel", "--'", "813", "!@#", "813", "813", "Alb"]

and I would like to have it sorted like:

[813, 813, 813, --', !@#, Alb, Bea, Hel, hel]

I have some code that gets pretty close but there is still one bug that I cannot figure out. Currently the program is producing this.

[813, 813, 813, Alb, --', !@#, Bea, Hel, hel]

Below is the code that I currently have

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
import java.util.Arrays;
import java.util.Comparator;


class Main {
  public static void main(String[] args) {
    List<String> list = Arrays.asList("Bea", "hel", "Hel", "--'", "813", "!@#", "813", "813", "Alb");

    Collections.sort(list, STANDARD_ALPHABETICAL_ORDER);
    System.out.println(list);

  }


  public final static Comparator<String> STANDARD_ALPHABETICAL_ORDER =
    (a,b) -> {
        String newA = a.replaceAll("[^a-zA-Z0-9]", "");
        String newB = b.replaceAll("[^a-zA-Z0-9]", "");
        int na = newA.length();
        int nb = newB.length();
        int r;
        int n;
        if (na < nb) {
            r = -1;
            n = na;
        } else if (na > nb) {
            r = -1;
            n = nb;
        } else {
            r = 0;
            n = na;
        }
        for (int i = 0; i < n; ++i) {
            char ca = newA.charAt(i);
            char cb = newB.charAt(i);
            if (ca != cb) {
                if (Character.isDigit(ca) && !Character.isDigit(cb)) {
                  return -1;
                } else if (!Character.isDigit(ca) && Character.isDigit(cb)) {
                  return 1;
                } else if (ca > cb ) {
                  return 1;
                } else {
                  return -1;
                }
            }
        }
        return r;
    };
}