Groovy read file line by line and store it into list

user_8575749 0
Viewed 6940

I have a file called apps.txt which has three app names in it

frontendapp

authorizationservice

connectorservice*

In jenkins pipeline i want to perform some operation on them one by one so i am trying to get them in groovy list using this code -

                    list = readFile.readFileLineByLine("${workspace}/apps.txt").collect {it}
                    for (item in list) {
                        println "I need to perform some operations on files"
                    }

But getting groovy.lang.MissingPropertyException. If i use file class like this - list = new File("${workspace}/apps.txt").collect {it} then it search for a file on Jenkins master node only and i get fileNotFoundException.

If i use list = readFile("${workspace}/apps.txt").collect {it} then list gets values character by character. How i can get app names from apps.txt inorder to perform operation on each app.

devops jenkins groovy
2 Answers

Your attempts are close, but mix things up.

Those are working ways:

def list = new File("${workspace}/apps.txt").text.readLines()

Note the .text call inbetween.

def list = readFile("${workspace}/apps.txt").readLines()

Or with the helper Jenkins provides.

Side note: .collect{it} is just .collect() - and usually is only needed to copy a list. Since the read lines from the file are already eagerly read, those are copies.

user_31813920

This work for me in a windows worker

script {
       def list = readFile("filesChanged").readLines()
       for(item in list){
          print item
          bat('type '+item) 
          }    
        }
user_37501930
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