Is there a way to make the following code more efficient? Namely, how can I avoid the need to first make the empty dict?
lst = [1,1,2,2,3,4,4,4]
dct = {}
dct = {num: lst.count(num) for num in lst if num not in dct}
Thank you.
Add dict key from list if list value isn't already a dict key
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2 Answers
You may use a set():
lst = [1,1,2,2,3,4,4,4]
dct = {key: lst.count(key) for key in set(lst)}
print(dct)
Which yields
{1: 2, 2: 2, 3: 1, 4: 3}
@Sushanth's solution is the best optimized:
import collections
lst = [1,1,2,2,3,4,4,4]
dct = collections.Counter(lst)
print(dct)
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