I'm trying to match all the non whitespace characters after a string in Regex. In this example, I want to match "b" without the whitespaces and the slashes around it:
a: /b/
I tried using (?<=a:)([^\s\/]+) but it doesn't work.
Matching all non whitespace characters after a string in Regex
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1 Answers
You still need to account for / before b, not just for whitespace.
You may use a \K based regex (if your regex flavor is PCRE/Onigmo/Boost):
a:\s*\/\K[^\s\/]+
See the regex demo.
Also, if you are using a regex engine that supports unknown width lookbehind patterns, you may use
(?<=a:\s*\/)[^\s\/]+
See this regex demo.
Else, you need to capture your substring with parentheses:
a:\s*\/([^\s\/]+)
See this regex demo.
Details
a:- aa:string\s*- 0+ whitespaces\/- a/char\K- a match reset operator[^\s\/]+- 1+ chars other than whitespace and/.
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