Is there way to return the name of a function to a string in Rust?

user_13854847 0
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So my question is whether this is possible, and if it is, how would one implement this. For example,

fn some_fn(){}
let name = get_name_of(some_fn);
println!({}, name);

Which outputs

some_fn

Would an implementation like this be possible?

rust
1 Answers

No, this currently does not seem to be possible as of 1.44.

Depending on your use case, you could of course still manually specify the name using macros such as println! or format the given function using stringify!.

For example, the following will print fn: some_fn:

fn main() {
    println!("fn: {}", std::stringify!(some_fn));
}

fn some_fn() {}

The downside is that it simply prints the given argument and does not allow you to get the actual function name. Here's an example where it fails, as fn: f and not fn: some_fn will be returned:

fn main() {
    some_fn_as_param(&some_fn);
}

fn some_fn() {}

fn some_fn_as_param(f: &dyn Fn()) {
    println!("fn: {}", stringify!(f));
}

As mentioned in the comments, talk of such a macro for rust can be tracked here:

user_11139130
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