I have written some code to try to solve this challenge, but its not working, i can't seem to figure out where it went wrong, i can find the answer online but that's not the point i'm trying to see why my code doesn't work.
question:
Given a set of candidate numbers (candidates) (without duplicates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target.
The same repeated number may be chosen from candidates unlimited number of times.
Input: candidates = [2,3,6,7], target = 7,
A solution set is:
[
[7],
[2,2,3]
]
this is what i have came up with:
class Solution {
public List<List<Integer>> combinationSum(int[] candidates, int target) {
List<List<Integer>> res = new ArrayList<>();
helper(res,new ArrayList<Integer>(), candidates,target,0,0);
return res;
}
//current = current sum, we want it to be target
//start is index we are at and where the for loop starts
public void helper(List<List<Integer>> res, List<Integer> temp, int[] nums, int target, int current, int start){
if(start>=nums.length){
return;
}
if(current>=target){
if(current==target){
res.add(new ArrayList<>(temp));
}
temp.remove(temp.size()-1);
helper(res,temp,nums,target,current-nums[start],start+1);
return;
}
for(int i=start; i<nums.length; i++){
temp.add(nums[i]);
helper(res,temp,nums,target,current+nums[i],start);
}
}
}
explanation of my code:
so i am trying to use recursion backtracking here. i keep for looping an element in the array till the sum is >= target.if its >target i remove the last element since that made it bigger than target and try the other ones. if its = target i add it to result and i remove last element to try find more combinations.
but apparently i am getting error in this line:
temp.remove(temp.size()-1); //saying index out of bounds i am trying to remove when arraylist is empty
so it isnt running how i thought, because if the list is empty current should be 0 and it should even enter that if loop and should never be removed but it is and i am not sure why.
thanks.