So I am currently learning prolog and I can't get my head around how this language works. "It tries all the possible solutions until it finds one, if it doesn't it returns false" is what I've read that this language does. You just Describe the solution and it finds it for you
With that in mind, I am trying to solve the 8 queens problem ( how to place 8 queens on a chess board without anyone threatening the others). I have this predicate, 'safe' that gets a list of pairs, the positions of all the queens and succeeds when they are not threatening each other.
When I enter in the terminal
?- safe([(1,2),(3,5)]).
true ?
| ?- safe([(1,3),(1,7)]).
no
| ?- safe([(2,2),(3,3)]).
no
| ?- safe([(2,2),(3,4),(8,7)]).
true ?
it recognizes the correct from the wrong answers, so it knows if something is a possible solution
BUT
when I enter
| ?- safe(L).
L = [] ? ;
L = [_] ? ;
it gives me the default answers, even though it recognizes a solution for 2 queens when I enter them.
here is my code
threatens((_,Row),(_,Row)).
threatens((Column,_),(Column,_)).
threatens((Column1,Row1),(Column2,Row2)) :-
Diff1 is Column1 - Row1,
Diff2 is Column2 - Row2,
abs(Diff1) =:= abs(Diff2).
safe([]).
safe([_]).
safe([A,B|T]) :-
\+ threatens(A,B),
safe([A|T]),
safe(T).
One solution I found to the problem is to create predicates 'position' and modify the 'safe' one
possition((0,0)).
possition((1,0)).
...
...
possition((6,7)).
possition((7,7)).
safe([A,B|T]) :-
possition(A),
possition(B),
\+ threatens(A,B),
safe([A|T]),
safe(T).
safe(L,X):-
length(L,X),
safe(L).
but this is just stupid, as you have to type everything explicitly and really really slow, even for 6 queens.
My real problem here, is not with the code itself but with prolog, I am trying to think in prolog, But all I read is Describe how the solution would look like and let it work out what is would be Well that's what I have been doing but it does not seem to work, Could somebody point me to some resources that don't teach you the semantics but how to think in prolog Thank you