What happens when I just use std::move without any assignment?
std::string s = "Moving";
std::move(s); //What happens on this line to s?
//is s still valid here?
What happens when std::move() is called without assignment
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1 Answers
std::move() doesn't move the passed object by itself; it just possibly enables move semantics for the object. It consists of a cast whose result you can use to select – if possible – the proper overload that supports move semantics. Therefore, in your code:
std::string s = "Moving";
std::move(s);
std::move(s) above casts s to an rvalue reference. The result of the casting is not used. The object s above is not actually moved, and it isn't modified.
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