Parse user-defined format in Java

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I am working on a format parser in Java and have some trouble with that. The format is stored so that users can change it to their likings.

format: '[prefix] [name] [suffix]: [msg]'

To put my values in the format I use String.replace() in Java.

format = getFormatTemplate(); // '[prefix] [name] [suffix]: [msg]'

format = format.replace("[prefix]", prefix); // prefix = "Hello";
format = format.replace("[name]", name); // name = "username";
format = format.replace("[suffix]", suffix); // suffix = "World";
format = format.replace("[msg]", msg); // msg = "Test message";

This will result in the output Hello username World: Test message as I expect. But when some parts of the string are empty there will be a space there.

When for example the suffix is empty the output will be Hello username : Test message note the space between the name and the :

How can I get rid of that so that some parts can be empty without breaking the user defined format?

Is there a better way to parse and apply the format?

formatting format java
1 Answers

The following method will do the job:

static String replace(String text, Map<String, String> values) {
    StringBuilder result = new StringBuilder();
    int textIdx = 0;
    for (int startIdx; (startIdx = text.indexOf('[', textIdx)) != -1; ) {
        int endIdx = text.indexOf(']', startIdx + 1);
        if (endIdx == -1)
            break;
        result.append(text.substring(textIdx, startIdx));
        textIdx = endIdx + 1;
        String value = values.get(text.substring(startIdx + 1, endIdx));
        if (value != null && ! value.isEmpty()) {
            result.append(value); // Replace placeholder with non-empty value
        } else if (result.length() != 0 && result.charAt(result.length() - 1) == ' ') {
            result.setLength(result.length() - 1); // Remove space before placeholder
        } else if (textIdx < text.length() && text.charAt(textIdx) == ' ') {
            textIdx++; // Skip space after placeholder
        }
    }
    result.append(text.substring(textIdx));
    return result.toString();
}

Test

public static void main(String[] args) {
    test("[prefix] [name] [suffix]: [msg]",
         Map.of("prefix", "Hello",
                "name", "username",
                "suffix", "World",
                "msg", "Test message"));
    test("[prefix] [name] [suffix]: [msg]",
         Map.of("name", "username",
                "suffix", "World",
                "msg", "Test message"));
    test("[prefix] [name] [suffix]: [msg]",
         Map.of("prefix", "Hello",
                "suffix", "World",
                "msg", "Test message"));
    test("[prefix] [name] [suffix]: [msg]",
         Map.of("prefix", "Hello",
                "name", "username",
                "msg", "Test message"));
    test("[prefix] [name] [suffix]: [msg]",
         Map.of("prefix", "Hello",
                "name", "username",
                "suffix", "World"));
    test("[prefix] [name] [suffix]: [msg]",
         Map.of());
}

static void test(String text, Map<String, String> values) {
    System.out.println('"' + replace(text, values) + '"');
}

Output

"Hello username World: Test message"
"username World: Test message"
"Hello World: Test message"
"Hello username: Test message"
"Hello username World:"
":"

Notice how multiple spaces are correctly eliminated when consecutive placeholders are missing/empty.

user_52211490
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