findAll() in Sequelize doesn't find a row created inside a transaction

user_13517716 0
Viewed 664

I'm having a problem when creating a row and later on selecting it while still under the same transaction.

Whenever I execute the following code I usually get an empty array and rarely get an array with the newly created row.

This is a sample of the code I run:

return seq.transaction((tx) => {
    const options = {transaction: tx};
    return model.create(user, options)
    .then(() => {
        return model.findAll({
            include: {
                all: true
            }
    }, options)
    .then((data) => ({
        console.log(data);
    });
});

Is there something basic I'm missing here? Thanks!

sequelize.js node.js mysql
1 Answers

I solved the problem. What I did wrong was giving the transaction to the findAll() function as an additional argument instead of part of the first argument's JSON.

So instead of:

return model.findAll({
    include: {
        all: true
    }
}, options)

I should've done:

return model.findAll({
    include: {
        all: true
    },
    transaction: options.transaction
});

Hope this solution will be helpful for other people.

user_135177160
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