kotlin, which function is called in the base class's init block

user_2987953 0
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having a base class and Child derived from it:

open class Base(var data: String) {

    init {
        doInit()
    }
    open protected fun doInit() {
       data += " in Base doInit()"
    }
}

class Child(data: String): Base(data) {

    init {
        doInit()
    }
    override fun doInit() {

        data += super.doInit() + " in Child doInit()"
    }
}

val obj = Child("child")

in Child("child"), the Base's init{} is called. which doInit() the Base's init{} is supposed to call, from the Base's one or the Child's one?

kotlin inheritance
1 Answers

If we define classes like this:

open class Base(var data: String) {

    init {
        doInit()
    }

    protected open fun doInit() {
        data += " in Base doInit()"
        println("in Base doInit()")
    }
}

class Child(data: String): Base(data) {

    override fun doInit() {
        data += " in Child doInit()"
        println("in Child doInit()")
    }
}

and create a child object:

val obj = Child("child")

we will see the output:

in Child doInit()

So when creating a child object and calling a function in base class that is overridden in child class, the child's function is called. That's called Polymorphism.

user_17316260
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