I am trying to remove the new line prior to "n=", replace with a space and contain the captured number in (), all these in MS Word's advanced find+replace, using wildcards.
Currently:
some preceeding text
n=1,233,023
Desired result:
some preceding text (1,233,023)
I've been struggling with ^13n=(*{1,}) and replace with " (\1)" (without the quotes) but it can't even match it. Any help please , appreciated. Thank you
MS Word does have weird ways in regular expressions. The following steps were succesfull for me (mine is in Dutch so please forgive any small translations errors):
Now with this done we can search for:
^13(n=[0-9,]{1,})
^13 - Match newline.( - Open capture group 1.
n= - Match "n=" literally.[,0-9]{1,} - Match a digit or commas at least 1 time.) - Close capture group 1.Replace by:
^s\1
^s\1 - A space followed by capture group 1.As mentioned I would consider the type of regular expressions Word is offering dodgy. Here you can read a bit more about it's flaws too. I couldn't create capture groups within a capture group neither was I able to create optional blocks of three consecutive digits and commas. Fortunately in your own attempt just knowing a newline followed by literally n= seemed enough.
Second to last note; because I'm Dutch my local parameter seperator is the semi-colon. This also reflects in this search and replace function its occurrence indicators meaning I used: ^13(n=[,0-9]{1;})
And one last note, another pattern I found worked for me was ^13(n=*^13), but since we had zero control of the pattern between n= and the paragraph end I would stick with my initial thought. The reason why the use of the * worked here is because we used it as an actual frequence of any characters between n= and ^13.
Before:
After:
The wildcard search term should be
(^13)([a-z])(=)([,0-9]{1,})
and the replacement is
(\4)
Note the first character above is a space.