Make quotient an integer if the number divides perfectly

user_13064271 0
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If perfect division occurs between two numbers, I want the result to be converted into an integer but if perfect division does not occur between the two numbers, then no change should be made. For example, 6/2 gives the result 3.0. Since this is perfect division, the 3.0 should be converted into 3. On the other hand if I have 14/4, which gives result 3.5, it should stay as it is since perfect division has not occurred.

Here by perfect division I mean a divided by b yields an integer

division python
4 Answers

This function checks if there is a remainder if you divide. If so, it's not an integer.

def divide_and_conquer(a, b):
    return a / b if a % b else a // b
user_23854900

Here is a step-by-step solution on how you can achieve that

# the numbers
num = 34
divisor = 17

# do the division
modula = num//divisor # modulus
quotient = num/divisor # normal division

# check if division is perfect
if modula  == quotient :
   result = int(quotient)
else:
   result = quotient
user_78060240

In python, you can use // to divide integers, and get an integer result. You can also use % to determine if two numbers divide perfectly (% returns the remainder, which is always zero if and only if the two numbers divide perfectly). To accomplish what you're asking, simply:

a = 6
b = 2
if a % b == 0:
  result = a // b
else:
  result = a / b

That said, you could also simply run the standard division and convert the result to an integer as well...

result = a / b
if result % 1 == 0:
  result = int(result)

However, in both of these cases, you might want to examine the broader context of what you're coding, because it can create real problems down the line if a variable is sometimes one data type, and other times a different data type - it might be best to leave the value as a float in every case until such time that you need for it to become an integer.

Note: Using '//' on two integers which do not divide perfectly will still result in an integer, as python will simply ignore the remainder. 6 // 4 = 1, 15 // 2 = 7.

user_92378420

You can use // division to get an int:

def divide(a, b):
    return a / b if a % b else a//b

divide(2, 5)   # 0.4 (float)
divide(10, 5)  # 2 (int)
user_14220960
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