JS Array.splice return original Array and chain to it

user_5144943 0
Viewed 809

I have a string with values like this a,b,c,d and want to remove a specific letter by index

So here is what I did str.split(',').splice(1,1).toString() and this is (obviously) not working since splice is returning the values removed not the original array

Is there any way to do the above in a one liner?

var str = "a,b,c,d";
console.log(str.split(',').splice(1,1).toString());

Thanks in advance.

splice javascript
4 Answers

You can use filter and add condition as index != 1.

var str = "a,b,c,d";
console.log(str.split(',').filter((x, i) => i != 1).toString());

user_96952860

Another strange solution. Destructure the array, remove the unwanted index, get an object and join the values of it.

var string = "a,b,c,d",
    { 1: _, ...temp } = string.split(',')

console.log(Object.values(temp).join(','));

user_14476750

The alternate way using regex replace

var str = "a,b,c,d";

console.log(str.replace(/,\w+/, ''))

user_80532740

Splice works in place, so oneliner is 

const arr = "a,b,c,d".split(','); arr.splice(1,1); console.log(arr.toString());

If you want an string in a oneliner, you have to hardcode the index in a filter

console.log("a,b,c,d".split(',').filter((item, i) => i != 1).toString())

Or two slices (not performant at all)

const arr = "a,b,c,d".split(',')
console.log([...arr.slice(0,1),...arr.slice(2)].toString())

user_2957830
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