Regex findall matches letters "a" to "z" in a string followed by another character

user_13575900 0
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Result should return list which contains letter a to c followed by another character

Text is aabbcc I would expect it return ['a', 'a', 'b', 'b', 'c']

import re
text = 'aabbcc'
result = re.findall(r'([a-c]).', text)
print(result)

but it returns ['a', 'b', 'c']

findall python-re python-3.x python regex
2 Answers

Use a non-capturing lookahead ([a-z](?=.)). This is basically the same as what you had, but doesn't capture the next character.

user_118820020

To make it work the way you have it, simply import regex instead of re module and use the overlapped parameter:

import regex
text = 'aabbcc'
result = regex.findall(r'([a-c]).', text, overlapped = True)
print(result)

Prints:

['a', 'a', 'b', 'b', 'c']

Otherwise a positive lookahead mentioned in comments and other answers is an option.

user_97581940
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