For loop using names of a dataframe in R

user_7928283 0
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I am working with COVID-19 data from my country by regions (3) in a dataframe. I want to use those columns of positive cases to generate other columns in which I want to calculate the growth in between rows. The dataframe:

> df
  Lima Arequipa Huánuco
1    1       NA      NA
2    6       NA      NA
3    6        1      NA
4    8        2       5
5    9        3       7
6    11       4       8

I want to use a for loop to calculate in a new column named as each df's column adding to its name "_dif" in which I have the row 1 - lag (row 1) for each column. So I used this code:

for(col in names(df)) {
  df[paste0(col, "_dif")] = df[col] - lag(df[col])
}

The output I want is the next one:

  Lima Arequipa Huánuco Lima_dif Arequipa_dif Huánuco_dif
1    1       NA      NA       NA           NA          NA
2    6       NA      NA       5            NA          NA
3    6        1      NA       0            NA          NA
4    8        2       5       2            1           NA
5    9        3       7       1            1           2
6    11       4       8       2            1           1

But when I see the df after the for loop I got this (only NA in the new columns):

  Lima Arequipa Huánuco Lima_dif Arequipa_dif Huánuco_dif
1    1       NA      NA       NA           NA          NA
2    6       NA      NA       NA           NA          NA
3    6        1      NA       NA           NA          NA
4    8        2       5       NA           NA          NA
5    9        3       7       NA           NA          NA
6    11       4       8       NA           NA          NA

Thanks in advance.

lag r for-loop
3 Answers

We can just use mutate with across from dplyr as the _all/_at suffixes are getting deprecated and in the newer version, across is more genneralized

library(dplyr)
df %>%
   mutate(across(everything(), ~ . - lag(.), names = "{col}_dif"))
#   Lima Arequipa Huánuco Lima_dif Arequipa_dif Huánuco_dif
#1    1       NA      NA       NA           NA          NA
#2    6       NA      NA        5           NA          NA
#3    6        1      NA        0           NA          NA
#4    8        2       5        2            1          NA
#5    9        3       7        1            1           2
#6   11        4       8        2            1           1

Or in base R

df[paste0(names(df), "_dif")] <- lapply(df, function(x) c(NA, diff(x)))

Or another option is

df[paste0(names(df), "_dif")] <- rbind(NA, diff(as.matrix(df)))

The issue in the OP's for loop is that df[col] is a still a data.frame with a single column, we need df[[col]] to extract as vector because lag needs a vector. According to ?lag

x - Vector of values

lag(df[1])
#  Lima
#1   NA

returns NA and it gets recycled

while, 

lag(df[[1]])
#[1] NA  1  6  6  8  9

therefore, if we change the code to

for(col in names(df)) {
  df[paste0(col, "_dif")] = df[[col]] - lag(df[[col]])
 }


df
#  Lima Arequipa Huánuco Lima_dif Arequipa_dif Huánuco_dif
#1    1       NA      NA       NA           NA          NA
#2    6       NA      NA        5           NA          NA
#3    6        1      NA        0           NA          NA
#4    8        2       5        2            1          NA
#5    9        3       7        1            1           2
#6   11        4       8        2            1           1

data

df <- structure(list(Lima = c(1L, 6L, 6L, 8L, 9L, 11L), Arequipa = c(NA, 
NA, 1L, 2L, 3L, 4L), Huánuco = c(NA, NA, NA, 5L, 7L, 8L)), 
  class = "data.frame", row.names = c("1", 
"2", "3", "4", "5", "6"))
user_37322710

In dplyr, you can use mutate_all : 

library(dplyr)
df %>%  mutate_all(list(diff = ~. - lag(.)))

#  Lima Arequipa Huánuco Lima_diff Arequipa_diff Huánuco_diff
#1    1       NA      NA        NA            NA           NA
#2    6       NA      NA         5            NA           NA
#3    6        1      NA         0            NA           NA
#4    8        2       5         2             1           NA
#5    9        3       7         1             1            2
#6   11        4       8         2             1            1

Or shift in data.table

library(data.table)
setDT(df)[, (paste0(names(df), '_diff')) := .SD - shift(.SD)]
user_39629140

You almost had it. 

df <- read_table("V  Lima  Arequipa    Huanuco
1    1       NA      NA
2    6       NA      NA
3    6        1      NA
4    8        2       5
5    9        3       7
6    11       4       8")

for(col in names(df)) {
  df[paste0(col, "_dif")] <- df[col] - lag(df[col], default = 0)
}
df

# A tibble: 6 x 8
      V  Lima Arequipa Huanuco V_dif Lima_dif Arequipa_dif Huanuco_dif
  <dbl> <dbl>    <dbl>   <dbl> <dbl>    <dbl>        <dbl>       <dbl>
1     1     1       NA      NA     1        1           NA          NA
2     2     6       NA      NA     2        6           NA          NA
3     3     6        1      NA     3        6            1          NA
4     4     8        2       5     4        8            2           5
5     5     9        3       7     5        9            3           7
6     6    11        4       8     6       11            4           8

You didn't set lag's default to 0, so it went to NA.

user_60040160
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