When I try to use parse this way: parse(Int64, "3.1459"), I get an error, because '.' is an invalid base 10 digit. I know the error gets raised because of the period, but is there any particular reason why Julia couldn't convert a float string to a integer like this? Any other way to do it?
Why can't parse transform float string into int?
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2 Answers
Well, it isn't an integer so it isn't really clear what it should return. You could just parse it as a float and then round it as you want, e.g:
julia> v = parse(Float64, "3.1459")
3.1459
julia> trunc(Int, v)
3
julia> ceil(Int, v)
4
julia> round(Int, v)
3
I'm not sure the error gets raised because of the period - rather because you can parse a decimal into an integer without specifying how you want to round:
julia> parse(Float64, "3.14159")
3.14159
julia> Int(round(parse(Float64, "3.14159")))
3
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