printf("\e[2J\e[0;0H");
What does this line mean?
Can I know what to learn and from where to understand this statement?
2 Answers
"\e" as an escape sequence is not part of the C standard.
A number of compilers treat the otherwise undefined behavior as a character with the value of 27 - the ASCII escape character.
Alternative well defined code:
//printf("\e[2J\e[0;0H");
printf("\x1B[2J\x1b[0;0H");
printf("\033[2J\033[0;0H");
#define ESC "\033"
printf(ESC "[2J" ESC "[0;0H");
The escape character introduces ANSI escape sequences as well answered in @Mickael B.. Select terminals implement some of these sequences.
They are ANSI escape sequences
These sequences define functions that change display graphics, control cursor movement, and reassign keys.
It starts with \e[ and the following characters define what should happen.
2J: clears the terminal
Esc[2JErase Display: Clears the screen and moves the cursor to the home position (line 0, column 0).
0;0H moves the cursor to the position (0, 0)
Esc[Line;ColumnHCursor Position: Moves the cursor to the specified position (coordinates).
See also:
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