All centers coincide on K-Means clustering

I am trying to apply K-Means through the following code-snippet in Python. Basically, the arr is a numpy array having values in three columns (Data with Multiple Features that I want to cluster). Here, I have used the following values: cv.TERM_CRITERIA_EPS = 1.0, cv.TERM_CRITERIA_MAX_ITER = 10 and attempts = 10. (as per the default values in the OpenCV documnetation link above).

To be specific, my three column arr is a RGB image, that is reshaped such that each column represents a color channel.

import cv2
import numpy as np 

Z = np.float32(arr)
criteria = (cv2.TERM_CRITERIA_EPS + cv2.TERM_CRITERIA_MAX_ITER, 10, 1.0)
ret, label, center = cv2.kmeans(Z, 4, None, criteria, 10, cv2.KMEANS_RANDOM_CENTERS)
labelToUse = (label.flatten()).astype('int32')
centerToUse = center.astype('float64')

While this gives me perfect results 70% of the time, but in 30% of the time I'm experiencing a weird case, as in the picture below (left one is centerToUse, right one is labelToUse). That is, all my cluster centers are (0, 0, 0), while labels are 0 for all the data points, except the last three (3, 2 and 1 respectively). Also, for the same arr, in some runs this abnormal case arises while in others, the results are just perfect.

Can anyone suggest me, about what should be my approach to eliminate this abnormality. I want to get decent results from K-Means each time, and not wait for good fortune. Also (don't know though whether this is relevant or not here), the situation is same in the scikit-learn representation of K-Means. This improves a bit if I increase n_init and max_iter to 30 and 300 respectively, but still persists. K-Means++ initialization also does not help.

EDIT: Based on the comment of @dhanushka, I recorded the compactness value on using cv2.KMEANS_PP_CENTERS. It came as follows (picture below), i.e. compactness = 61555894.92789865 when the output is perfect, while compactness = 0.0 for the 'weird' case (all centers at (0,0,0)). Possible that it exceeds the limit for the data-type.

Any leads in this issue will be highly appreciated.