I would like to filter a Dataframe. The resulting dataframe should contain all the rows where in any of a number of columns contain any of the words of a list.
I started to use for loops but there should be a better pythonic/pandonic way.
Example:
# importing pandas
import pandas as pd
# Creating the dataframe with dict of lists
df = pd.DataFrame({'Name': ['Geeks', 'Peter', 'James', 'Jack', 'Lisa'],
'Team': ['Boston', 'Boston', 'Boston', 'Chele', 'Barse'],
'Position': ['PG', 'PG', 'UG', 'PG', 'UG'],
'Number': [3, 4, 7, 11, 5],
'Age': [33, 25, 34, 35, 28],
'Height': ['6-2', '6-4', '5-9', '6-1', '5-8'],
'Weight': [89, 79, 113, 78, 84],
'College': ['MIT', 'MIT', 'MIT', 'Stanford', 'Stanford'],
'Salary': [99999, 99994, 89999, 78889, 87779]},
index =['ind1', 'ind2', 'ind3', 'ind4', 'ind5'])
df1 = df[df['Team'].str.contains("Boston") | df['College'].str.contains('MIT')]
print(df1)
So it is clear how to filter columns individually that contain a particular word
further on it is also clear how to filter rows per column containing any of the strings of a list:
df[df.Name.str.contains('|'.join(search_values ))]
Where search_values contains a list of words or strings.
search_values = ['boston','mike','whatever']
I am looking for a short way to code
#pseudocode
give me a subframe of df where any of the columns 'Name','Position','Team' contains any of the words in search_values
I know I can do
df[df['Name'].str.contains('|'.join(search_values )) | df['Position'].str.contains('|'.join(search_values )) | df['Team'].contains('|'.join(search_values )) ]
but if I would have like 20 columns that would be a mess of a line of code
any suggestion?
EDIT Bonus: When looking in a list of columns i.e. 'Name','Position','Team' how to include also the index? passing ['index','Name','Position','Team'] does not work.
thanks.
I had a look to this: https://www.geeksforgeeks.org/get-all-rows-in-a-pandas-dataframe-containing-given-substring/
https://kanoki.org/2019/03/27/pandas-select-rows-by-condition-and-string-operations/