Mapping a throwing function in swift---double try

user_4386239 0
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A very small question. When I try to map a throwing function in Swift, the compiler makes me use the try keyword twice. For a toy example: 

public func combineFiles(files: [String]) throws -> String {
    let strings = try files.map { try String(contentsOfFile: $0) }
    return strings.joined(separator: "\n\n")
}

Both of the try keywords in the second line seem to be necessary in order to get this to compile. But this just feels super-wrong to me---is there a way to do this kind of operation without a second try statement?

swift higher-order-functions error-handling
1 Answers

Technically, you could have a single try if you avoid calling map:

func combineFiles(files: [String]) throws -> String {
    var results: [String] = []
    for file in files {
        results.append(try String(contentsOfFile: file))
    }
    return results.joined(separator: "\n\n")
}

But I think that’s going the wrong direction. I’d just embrace the two try pattern that rethrowing functions like map entail.

I’d lose strings, though:

func combineFiles(files: [String]) throws -> String {
    try files.map { try String(contentsOfFile: $0) }
        .joined(separator: "\n\n")
}
user_12718260
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