Problem with minimum element of an array in windows form application

user_13230219 0
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I am learning how to create simple .NET applications. In this application I'm adding numbers in array of integers from TextBox, and display the biggest and smallest number from this array in the ListBox. The problem is that when I'm finding minimum number using Min method it always gives me 0, however Max method works just fine

    public partial class Form1 : Form
    {
        // ...

        int[] array = new int[100];
        int counter = 0;
        private void button1_Click_1(object sender, EventArgs e)
        {
            for (int i = 0; i <= counter; i++)
            {
                array[i] = Convert.ToInt32(txtInsertNumber.Text);
            }
            counter++;
        }

        private void btnShowMinMax_Click_1(object sender, EventArgs e)
        {
            listBox1.Items.Clear();
            int max = array.Max();
            int min = array.Min();

            int maxIndex = Array.IndexOf(array, max);
            int minIndex = Array.IndexOf(array, min);

            listBox1.Items.Add(array[maxIndex] + " " + array[minIndex]);
        }
    }

Screen of application interface

default .net c#
2 Answers

Your array int[] array = new int[100]; is initialized with 100 integers with the default value of 0. That's why the minimum value is 0.

The solution would be to have an array of Nullable<int> to differenciate "no value" null from real values. Example:

int[] a = new int[50];
Console.WriteLine(a.Min()); // prints "0"

Nullable<int>[] b = new Nullable<int>[100];
Console.WriteLine(b.Min()); // prints ""
user_71359770

Also, you can use List<int> with a predefined size. 

    static void Main(string[] args)
    {
        var list = new List<int>(10);
        list.Add(1);
        list.Add(2);

        var min = list.Min(); //  will be 1
        var max = list.Max(); // will be 2 
    }
user_28039460
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