Extract Foreign Key Constraint and Reference Column from SQL Server table's query

I use the following query to list all table constraints, which works well in extracting constraint needed to alter the output table (adding primary key, unique constraint).

select table_view,
    object_type, 
    constraint_type,
    constraint_name,
    details
from (
    select schema_name(t.schema_id) + '.' + t.[name] as table_view, 
        case when t.[type] = 'U' then 'Table'
            when t.[type] = 'V' then 'View'
            end as [object_type],
        case when c.[type] = 'PK' then 'Primary key'
            when c.[type] = 'UQ' then 'Unique constraint'
            when i.[type] = 1 then 'Unique clustered index'
            when i.type = 2 then 'Unique index'
            end as constraint_type, 
        isnull(c.[name], i.[name]) as constraint_name,
        substring(column_names, 1, len(column_names)-1) as [details]
    from sys.objects t
        left outer join sys.indexes i
            on t.object_id = i.object_id
        left outer join sys.key_constraints c
            on i.object_id = c.parent_object_id 
            and i.index_id = c.unique_index_id
       cross apply (select col.[name] + ', '
                        from sys.index_columns ic
                            inner join sys.columns col
                                on ic.object_id = col.object_id
                                and ic.column_id = col.column_id
                        where ic.object_id = t.object_id
                            and ic.index_id = i.index_id
                                order by col.column_id
                                for xml path ('') ) D (column_names)
    where is_unique = 1
    and t.is_ms_shipped <> 1
    union all 
    select schema_name(fk_tab.schema_id) + '.' + fk_tab.name as foreign_table,
        'Table',
        'Foreign key',
        fk.name as fk_constraint_name,
        schema_name(pk_tab.schema_id) + '.' + pk_tab.name
    from sys.foreign_keys fk
        inner join sys.tables fk_tab
            on fk_tab.object_id = fk.parent_object_id
        inner join sys.tables pk_tab
            on pk_tab.object_id = fk.referenced_object_id
        inner join sys.foreign_key_columns fk_cols
            on fk_cols.constraint_object_id = fk.object_id
    union all
    select schema_name(t.schema_id) + '.' + t.[name],
        'Table',
        'Check constraint',
        con.[name] as constraint_name,
        con.[definition]
    from sys.check_constraints con
        left outer join sys.objects t
            on con.parent_object_id = t.object_id
        left outer join sys.all_columns col
            on con.parent_column_id = col.column_id
            and con.parent_object_id = col.object_id
    union all
    select schema_name(t.schema_id) + '.' + t.[name],
        'Table',
        'Default constraint',
        con.[name],
        col.[name] + ' = ' + con.[definition]
    from sys.default_constraints con
        left outer join sys.objects t
            on con.parent_object_id = t.object_id
        left outer join sys.all_columns col
            on con.parent_column_id = col.column_id
            and con.parent_object_id = col.object_id) a
order by table_view, constraint_type, constraint_name

https://dataedo.com/kb/query/sql-server/list-all-table-constraints

However, it does not work in case of foreign key as a foreign key constraint (column) and its reference column is needed.

ALTER TABLE row16.table_view
ADD CONSTRAINT row16.contraint_name
FOREIGN KEY (**row16....**) REFERENCES row16.details(**row16....**);

 || actual value

ALTER TABLE DBO.AREA
ADD CONSTRAINT FK_AREA_DOM_AIRLINE
FOREIGN KEY (**should be 'airline_cd'**) REFERENCES DBO.DOM_AIRLINE(**should be 'cd'**);

I wanted to add foreign constraint using the following statement, but I don't know how I could define foreign key constraint and its reference column here..

I feel like there might be a need to make some changes to the table constraints query, but I just start learning SQL recently so I'm not familiar with the whole concept yet...

Here's table relation for reference

Please let me know if you need any more infos. Appreciated all your helps!