Simplest way to split a csv string into an array that works for both bash & zsh

user_2030088 0
Viewed 899

What is the simplest way to split a csv string into an array using only builtins that works for both bash & zsh?

I have separate code that works for bash and for zsh, but I haven't yet found anything that works for both:

csv='a,b,c'

# Works in zsh, but not in bash
array=(${(s:,:)csv})

# Works in bash, but not in zsh
array=(${csv//,/ }) # This requires that $IFS contains the space character
zsh arrays bash split string
1 Answers

As pointed out in the comments, there are two nearly identical commands, one for each shell.

# bash
IFS=, read -ra array <<< "$csv"

# zsh
IFS=, read -rA array <<< "$csv"

The syntax is the same; the only difference is whether you use a or A as the option to read. I would recommend adding a conditional statement that detects which shell is executing the script, then use a variable to store the correct option.

if [ -n "$BASH_VERSION" ]; then
    arr_opt=a
elif [ -n "$ZSH_VERSION" ]; then
    arr_opt=A
fi

IFS=, read -r"$arr_opt" array <<< "$csv"

Checking for non-empty version parameters isn't foolproof, but it should be good enough.

user_11268410
Related