If your line has starting and ending points [x1, y1] and [x2, y2], then the line equation is:
y - y1 = m * (x - x1), where m = (y2 - y1)/(x2-x1)
Then you can check if a point belongs to the line or not, substituting either x or y, and checking if the other matches the line equation.
In Pyhton:
# the two points that define the line
p1 = [1, 6]
p2 = [3, 2]
# extract x's and y's, just for an easy code reading
x1, y1 = p1
x2, y2 = p2
m = (y2-y1)/(x2-x1)
# your centroid
centroid = [2,4]
x3, y3 = centroid
# check if centroid belongs to the line
if (m * (x3-x1) + y1) == y3:
print("Centroid belongs to line")
But probably...
...you'll have better results calculating the distance between red dot and the line (distance from a point to a line), and then checking if it is near enough (i.e. distance less than some value).
In Python:
# points that define the line
p1 = [1, 6]
p2 = [3, 2]
x1, y1 = p1
x2, y2 = p2
centroid = [2,4]
x3, y3 = centroid
# distance from centroid to line
import math # to calculate square root
dist = abs((y2-y1)*x3 - (x2-x1)*y3 + x2*y1 - y2*x1)/math.sqrt((y2-y1)**2 + (x2-x1)**2)
if dist < some_value:
print("Near enough")