Consider the df1 pandas DataFrame. I would like to transform this DataFrame to have a count per each date and concept (see df2).
import pandas as pd
inp_data = [
{'date': '2020-02-01', 'concepts': [{'surfaceForm': 'ABC'}, {'surfaceForm': 'DEF'}]},
{'date': '2020-02-01', 'concepts': [{'surfaceForm': 'ABC'}, {'surfaceForm': 'XYZ'}]},
{'date': '2020-02-02', 'concepts': [{'surfaceForm': 'XYZ'}]}
]
df1 = pd.DataFrame(inp_data, columns=['date', 'concepts'])
# transform df1 into df2...
# goal
out_data = [
{'day': '2020-02-01', 'concept': 'ABC', 'count': 2},
{'day': '2020-02-01', 'concept': 'DEF', 'count': 1},
{'day': '2020-02-01', 'concept': 'XYZ', 'count': 1},
{'day': '2020-02-02', 'concept': 'XYZ', 'count': 1},
]
df2 = pd.DataFrame(out_data, columns=['day', 'concept', 'count'])
Note that the df1 date becomes day in df2; and each object in concepts in df1 is regarded its own concept in df2.
I could hack it together with iterating over the rows of df1 which obviously has lots of performance problems and isn't the pandas way. Then I wanted to run it for a magnitude bigger DataFrame which didn't work in a timely manner.
For reference, here's the hacky way:
import pandas as pd
columns = ['concept', 'day']
def concept_occurence(row, columns):
insert_list = list()
for c in row['concepts']:
sf = c['surfaceForm']
insert_list.append({'concept': sf, 'day': row['date']})
return pd.DataFrame(insert_list, columns=columns)
df2 = pd.DataFrame(columns=columns)
for index, row in df1.iterrows():
concept_map = concept_occurence(row, columns)
df2 = df2.append(concept_map, ignore_index=True)