I can run my node.js application with es6 modules with the --experimental-modules flag as follows:
node --experimental-modules ./bin/www
How can I do the same when debuggging the application from VS Code, which uses the launch.json configuration file?
{
"version": "0.2.0",
"configurations": [
{
"type": "node",
"request": "launch",
"name": "Launch Program",
"program": "${workspaceFolder}\\bin\\www",
}
]
}
Instead of using the "program" key you can pass the needed flag in "args" before you pass it your module.
node --experimental-modules ./myModule
{
"version": "0.2.0",
"configurations": [
{
"name": "run module",
"type": "node",
"request": "launch",
"args": ["--experimental-modules", "${workspaceFolder}/myModule"]
}
]
}
I only learned this last week trying to do the same thing with a Python program.
The official guidance is to use the runtimeArgs attribute like this:
{
"name": "Launch Program",
"request": "launch",
"type": "node",
"runtimeArgs": ["--experimental-modules"],
"program": "${workspaceFolder}\\bin\\www"
}
Which will run the following terminal command:
node.exe --experimental-modules .\bin\www
See Also: How to start nodejs with custom params from vscode