i = 0
d = input("Enter the no. you want ")
while i < 11 :
print(i * d)
i+= 1
It is supposed to give multiplication table of d but it gives the following result for eg. '3' instead
3
33
333
3333
33333
333333
3333333
33333333
333333333
3333333333
The input() returns a string not an int and if you multiply a string in Python with an integer num, then you will get a string repeated num times. For example,
s = "stack"
print(s * 3) # Returns "stackstackstack"
You need to use int() constructor to cast the input from str to int.
d = int(input("Enter the no. you want "))
Try this:
d = int(input("Enter the no. you want "))
for i in range(1,11):
print(i * d)
In the above code, I have replaced your while loop construct with for loop and range() to get sequence of numbers.
BONUS:
To print/display the table in a nice and better way, try the below code:
for i in range(1,11):
print("%d X %d = %d" % (d, i, i * d))
Outputs:
Enter the no. you want 2
2 X 1 = 2
2 X 2 = 4
2 X 3 = 6
2 X 4 = 8
2 X 5 = 10
2 X 6 = 12
2 X 7 = 14
2 X 8 = 16
2 X 9 = 18
2 X 10 = 20