SQL sum grouped by field with all rows

user_3936931 0
Viewed 116

I have this table:

id  sale_id  price
-------------------
1     1       100
2     1       200
3     2       50 
4     3       50

I want this result:

id  sale_id  price  sum(price by sale_id)
------------------------------------------
1     1       100    300
2     1       200    300
3     2       50      50
4     3       50      50

I tried this:

SELECT id, sale_id, price, 
(SELECT sum(price) FROM sale_lines GROUP BY sale_id) 
FROM sale_lines

But get the error that subquery returns different number of rows. How can I do it?

I want all the rows of sale_lines table selecting all fields and adding the sum(price) grouped by sale_id.

rows group-by sum sql
4 Answers

You can use window function :

sum(price) over (partition by sale_id) as sum

If you want sub-query then you need to correlate them :

SELECT sl.id, sl.sale_id, sl.price, 
       (SELECT sum(sll.price) 
        FROM sale_lines sll 
        WHERE sl.sale_id = sll.sale_id 
        ) 
FROM sale_lines sl;
user_55294450

Don't use GROUP BY in the sub-query, make it a co-related sub-query:

SELECT sl1.id, sl1.sale_id, sl1.price, 
       (SELECT sum(sl2.price) FROM sale_lines sl2 where sl2.sale_id = sl.sale_id) as total 
FROM sale_lines sl1
user_3303150

In addition to other approaches, You can use CROSS APPLY and get the sum. 

SELECT id, sale_id,price, Price_Sum
FROM YourTable AS ot
CROSS APPLY
(SELECT SUM(price) AS Price_Sum
FROM YourTable
WHERE sale_id = ot.sale_id);
user_6349350 
SELECT t1.*, 
       total_price 
FROM   `sale_lines` AS t1 
       JOIN(SELECT Sum(price) AS total_price, 
                   sale_id 
            FROM   sale_lines 
            GROUP  BY sale_id) AS t2 
         ON t1.sale_id = t2.sale_id
user_9901770
Related